Trigonometry Problem #1 The electricity supplied to your house is called vary electric topical (AC) because the accepted varies sinusoidally with clock. The potential which causes the actual to flow besides varies sinusoidally with eon. twaine the current and the potency launch a frequency of 60 cycles per second which corresponds to a stage of 1/60 of a second, but current and voltage have different signifier shifts. We will be go out equations for the voltages and the current as give ways of time base upon the equationf(t)=Acos[B(x-C)]+D. Under the assumption that current and voltage argon both sinusoidal functions of time (t, in seconds) and both have the equivalent frequency of 60 cycles per second (period=1/60), allow C be the current in Amperes (Amps) with a supreme current of 5 Amps at zero seconds (t=zero). Let V be the voltage that is leading the current (leading synonymous to a controvert variety shift) by .003 seconds, meaning voltage reach es its uttermost of 180 volts .003 sec before the current reaches its maximum. Both functions write down at zero- at that place are no soma shifts. interrogative 1, Part A. Current as a function of time: Based upon the addicted information, we will be determining the amplitude (A), period (and thus, B), and the phase shift (C).

Given information states there is not a phase shift, therefore the harbor of D is zero and does not need to be record throughout the problem. The Amplitude (A) or maximum for the current has been given: 5 Amps. This indicates that the range will span from -5 to 5 o n the y-axis. It is also given that at t=zer! o (time=zero) the current is play off to 5 Amps, meaning there is a negative phase shift (or phase shift to the left). A=5 B is calculated by the equation B=2?/( 1/60) , where p (period length)= 1/60 or the length of one full cycle found from the frequency which is 60cycles per second. So p is 1/60 of a second long. Using my TI-84, I found B: B=2?/P ? B=2?/( 1/60) B=...If you want to get a full essay, order it on our website:
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